C 语言实例 - 斐波那契数列

斐波那契数列指的是这样一个数列 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233，377，610，987，1597，2584，4181，6765，10946，17711，28657，46368........

这个数列从第3项开始，每一项都等于前两项之和。

实例 - 输出指定数量的斐波那契数列

#include <stdio.h> int main() { int i, n, t1 = 0, t2 = 1, nextTerm; printf("输出几项: "); scanf("%d", &n); printf("斐波那契数列: "); for (i = 1; i <= n; ++i) { printf("%d, ", t1); nextTerm = t1 + t2; t1 = t2; t2 = nextTerm; } return 0; }

运行结果：

输出几项: 10
斐波那契数列: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34,

实例 - 输出指定数字前的斐波那契数列

#include <stdio.h> int main() { int t1 = 0, t2 = 1, nextTerm = 0, n; printf("输入一个正数: "); scanf("%d", &n); // 显示前两项 printf("斐波那契数列: %d, %d, ", t1, t2); nextTerm = t1 + t2; while(nextTerm <= n) { printf("%d, ",nextTerm); t1 = t2; t2 = nextTerm; nextTerm = t1 + t2; } return 0; }

运行结果：

输入一个正数: 100
斐波那契数列: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89,

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