Python 构建URL

Python 构建URL

Python requests模块可以帮助构建URLS并动态处理URL值。可以以编程方式获取URL的任何子目录,然后可以用新值替换其中的一部分以构建新的URL。

建立网址

下面的示例使用urljoin在URL路径中获取不同的子文件夹。urljoin方法用于将新值添加到基本URL。

 
# Filename : example.py
# Copyright : 2020 By Codebaoku
# Author by : www.yapf.com
# Date : 2020-08-25
from requests.compat import urljoin
 base='https://stackoverflow.com/questions/3764291'
 print urljoin(base,'.')
 print urljoin(base,'..')
 print urljoin(base,'...')
 print urljoin(base,'/3892299/')
 url_query = urljoin(base,'?vers=1.0')
 print url_query
 url_sec = urljoin(url_query,'#section-5.4')
 print url_sec
  
 

执行上面示例代码,得到以下结果:

 
# Filename : example.py
# Copyright : 2020 By Codebaoku
# Author by : www.yapf.com
# Date : 2020-08-25
https://stackoverflow.com/questions/
 https://stackoverflow.com/
 https://stackoverflow.com/questions/...
 https://stackoverflow.com/3892299/
 https://stackoverflow.com/questions/3892299?vers=1.0
 https://stackoverflow.com/questions/3892299?vers=1.0#section-5.4
  
 

分割网址

URL也可以分为多个主要地址。如下所示,使用urlparse方法分隔用于特定查询的附加参数或附加到URL的标记。

 
# Filename : example.py
# Copyright : 2020 By Codebaoku
# Author by : www.yapf.com
# Date : 2020-08-25
from requests.compat import urlparse
 url1 = 'https://docs.python.org/2/py-modindex.html#cap-f'
 url2='https://docs.python.org/2/search.html?q=urlparse'
 print urlparse(url1)
 print urlparse(url2)
  
 

执行上面示例代码,得到以下结果:

 
# Filename : example.py
# Copyright : 2020 By Codebaoku
# Author by : www.yapf.com
# Date : 2020-08-25
ParseResult(scheme='https', netloc='docs.python.org', path='/2/py-modindex.html', params='', query='', fragment='cap-f')
 ParseResult(scheme='https', netloc='docs.python.org', path='/2/search.html', params='', query='q=urlparse', fragment='')
  
 

下一节:Python Web表单提交

Python 网络编程

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